wudb
春芽
共回答了17个问题采纳率:88.2% 举报
①y=(x+1)(x+2)(x+3)
y'=(x+1)'(x+2)(x+3)+(x+1)(x+2)'(x+3)+(x+1)(x+2)(x+3)'
=(x+2)(x+3)+(x+1)(x+3)+(x+1)(x+2)
=3x²+12x+11
②y=x^2/(sinx+cosx)
y'=【(x²)'(sinx+cosx)-x²(sinx+cosx)'】/(sinx+cosx)²
=[2x(sinx+cosx)-x²(cosx-sinx)/(sinx+cosx)²
1年前
7