[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)

vernal26 1年前 已收到2个回答 举报

tsintsun 幼苗

共回答了21个问题采纳率:100% 举报

[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
=[2sin50°*sin80°+sin10°*cos10°(cos10°+√3sin10°)/cos10°]*√2(sin80°)
=[2sin50°*sin80°+2sin10°(1/2cos10°+√3/2sin10°)]*√2(sin80°)
=[2sin50°*sin80°+2sin10°sin(30°+10°)]*√2(sin80°)
=[2sin50°*sin80°+2sin10°sin40°]*√2(sin80°)
=[2sin50°*cos10°+2sin10°cos50°]*√2(sin80°)
=2[sin60°]*√2(sin80°)
=√6sin80°

1年前

2

zzhfirst123 幼苗

共回答了3个问题 举报

[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
=[2sin50°*sin80°+sin10°*cos10°(cos10°+√3sin10°)/cos10°]*√2(sin80°)
=[2sin50°*sin80°+2sin10°(1/2cos10°+√3/2sin10°)]*√2(sin80°)
=[2sin50°*sin...

1年前

0
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