风灵紫
幼苗
共回答了26个问题采纳率:88.5% 举报
m=(2coswx,√3coswx-sinwx)=(2coswx,2cos(wx+π/6)),n=(sin(wx+π/6),sinwx)
则:f(x)=m·n=(2coswx,2cos(wx+π/6))·(sin(wx+π/6),sinwx)
=2coswx*sin(wx+π/6)+2cos(wx+π/6)*sinwx=2sin(2wx+π/6)
f(x)的最小正周期:T=2π/(2w)=π/w=π,故:w=1,即:f(x)=2sin(2x+π/6)
增区间:2kπ-π/2≤2x+π/6≤2kπ+π/2,k∈Z
即:kπ-π/3≤x≤kπ+π/6,k∈Z
1年前
4