心痛0114
幼苗
共回答了16个问题采纳率：93.8% 举报
x+2y+﹙4y²／x-2y﹚＋﹙4x²y／4y²-x²）
=[(x+2y)(x-2y) +4y²]／(x-2y﹚+ 4x²y／（4y²-x²）
=(x²-4y² +4y²）／(x-2y﹚+ 4x²y／[(2y+x)(2y-x)]
=x²／(x-2y﹚- 4x²y／[(x+2y)(x- 2y)]
=[x²(x+2y﹚- 4x²y]／[(x+2y)(x- 2y)]
=(x³-2x²y)／[(x+2y)(x- 2y)]
=x²(x-2y)／[(x+2y)(x- 2y)]
=x²／(x+2y)
1年前
5
