yy16160
幼苗
共回答了19个问题采纳率:94.7% 举报
一.m(O) = 98g * [(16*4)/(1*3 + 31 + 16*4) ] *100% * 98g = 64g
1.Mr[Mg(OH)2] = 24 + ( 16 + 1) * 2 = 58
2.H:Mg:O = (1*2 ) :24 :(16*2) = 2 :24 :32
3.O% = (16*2) / Mr[Mg(OH)2] *100% = 32 / 58 *100% = 55.2%
4.设xgMg(OH)2中含有氧元素32克,
xg * 55.2% = 32g
得:x = 58
1年前
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