卡布诺KBN 幼苗
共回答了26个问题采纳率:92.3% 举报
(1)在KNO3中,氮元素的质量分数为[14/39+14+16×3]×100%=13.9%;
硝酸钾因为含有氮元素与钾元素两种元素应属于复合肥;
(2)要配制150kg该营养液,需要水的质量为150kg×(1-35.4%)=96.9kg;
故答案为:
(1)13.9%;复合肥料;(2)96.9
点评:
本题考点: 元素的质量分数计算;用水稀释改变浓度的方法;常见化肥的种类和作用.
考点点评: 此题是对硝酸钾的相关知识的考查,解决的重点是掌握有关硝酸钾化学式的计算,属基础性知识考查题.
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