帮我用lingo编编程吧设X1,X2,X3……X46为46档长度肠衣分别的数,N成品捆数.则 Max Z＝N （成品捆数

model:
sets:
set1/1..46/:X;
endsets
ub=89.5;
lb=88.5;
max = N;
@sum(set1(i)|i#ge#1 #and# i#le#8:X(i))=19*N;
@sum(set1(i)|i#ge#9 #and# i#le#22:X(i))=7*N;
@sum(set1(i)|i#ge#23 #and# i#le#46:X(i))=4*N;
@sum(set1(i)|i#ge#1 #and# i#le#8:(3+0.5*(i-1))*X(i))=lb;
@sum(set1(i)|i#ge#9 #and# i#le#22:(7+0.5*(i-9))*X(i))=lb;
@sum(set1(i)|i#ge#23 #and# i#le#46:(14+0.5*(i-23))*X(i))=lb;
end
如果需要整数要求,则需要加上@for(set1(i):@gin(X));