dghua163
幼苗
共回答了16个问题采纳率:93.8% 举报
∵[(m^2-n^2)/(m^2+mn)]÷[(m^2-2mn+n^2)/(2n^2-2nm)]=1
∴[(m+n)(m-n)]/[m(m+n)]×[2n(n-m)]/(n-m)^2=1
∴(m-n)/m ×2n/(n-m)=1
∴2n/m=1
∴m=2n
∴m^2/(m^2-n^2)+(2mn-n^2)/(n^2-m^2)
=4n^2/(4n^2-n^2)+(4n^2-n^2)/(n^2-4n^2)
=4/3-3/3
=1/3
这种叙述的式子,理解起来可能会有偏差的.
1年前
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