啊奈耶识
幼苗
共回答了16个问题采纳率:93.8% 举报
private double JJ(double s,double e,double p,double c)
{
return c e ? e : c ) * p
}
double J = 奖金大大的
JJJ = JJ (0,10,0.1,J) + JJ(10,20,0.075,J) + JJ(20,40,0.05,J) + JJ(40,60,0.03,J) + JJ(60,100,0.015,J) + JJ(100,9999999999,0.01,J)
你看看,我就不用IF和Switch 哈哈
1年前
追问
8
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啊奈耶识
int J = 奖金大大的 int i = J % 10 switch(i) { case 0: return J * 0.1 case 1: return 10 * 0.1 + J * 0.075 case 2: case 3: return 10 * 0.1 + 10 * 0.75 + (j - 20) * 0.05 case 4: case 5: ...这个你会写吧 default: return 10 * 0.1 + 10 * 0.075 + 20 *0.05 + 20 * 0.03 + 20 * 0.015 + (J-100) * 0.01 } 这个是你要的吗?自己写写DEBUG吧,