2a^+3a+2 a^-a-5 3a^-4a-5 2a^-8a+5

原式=(2a+1+1/a+1)-(a-3+1/a+2)-(3a+2-1/a-2)+(2a-2-1/a-3)
=(1/a+1)-(1/a+2)+(1/a-2)-(1/a-3)
(a+2)(a-2)(a-3)-(a+1)(a-2)(a-3)+(a+1)(a+2)(a-3)-(a+1)(a+2)(a-2)
=---------------------------------------------------------------
(a+1)(a+2)(a-2)(a-3)
(a+2)(a-2)(a-3-a-1)+(a+1)(a-3)(a+2-a+2)
=--------------------------------------------
(a+1)(a+2)(a-2)(a-3)
4(1-2a)
= ---------------------------
(a+1)(a+2)(a-2)(a-3)
写了真么多,头都疼了,也没检查,方法估计就是这样,看看答案,做的对不对

这个问题简单...但是这里没有公式编辑器...没法说明....
你QQ多少，我+你语音解答你吧...

上面全部用因式分解 然后和下面消

用式除(或配方)方法得到:
(2a^+3a+2)/(a+1)=2a+1+1/(a+1);
(a^-a-5)/(a+2)=a-3+1/(a+2);
(3a^-4a-5)/(a-2)=3a+2-1/(a-2);
(2a^-8a+5)/(a-3)=2a-2-1/(a-3)
则原式
=[2a+1+1/(a+1)]-[a-3+1/(a+2)]-[3a+2-1/(a-2)]+[2a-2-1/(a-3)]
=4+[1/(a+1) -1/(a+2) +1/(a-2)-1/(a-3)]