seven镯
春芽
共回答了24个问题采纳率:87.5% 举报
f(x)=根号(3sin2x+2cos^2 *x)
=根号(3sin2x+1+cos2x)
=根号[(根10)*sin(2x+t) +1] (cost=3/根号10)
f(π/12)=根号(3sinπ/6+1+cosπ/6)
=根号(3/2+1+根3 /2)
=根号(5/2+根3 /2)
(2)f(x)=根号[(根10)*sin(2x+t) +1] (cost=3/根号10,t=arccos(3/根号10))
最小正周期为2π/2=π
单调增区间为:2kπ-π/2
1年前
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