计算:(5+1)(5的平方+1)(5的4次方+1).(5的32次方+1)+4分之一,

yy1221 1年前 已收到3个回答 举报

mobil65347 幼苗

共回答了28个问题采纳率:89.3% 举报

=4×(5+1)(5^2+1)(5^4+1)……(5^32+1)÷4+1/4
=(5-1)(5+1)(5^2+1)(5^4+1)……(5^32+1)÷4+1/4
=(5^2-1)(5^2+1)(5^4+1)……(5^32+1)÷4+1/4
=(5^4-1)(5^4+1)……(5^32+1)÷4+1/4
……
……
=(5^64-1)/4+1/4
=5^64/4-1/4+1/4
=5^64/4

1年前

2

evah201983 幼苗

共回答了590个问题 举报

[(5-1)(5+1)(5^2+1)(5^4+1)......(5^32+1)+1]/4
=[(5^2-1)(5^2+1)(5^4+1)...(5^32+1)+1]/4
=(5^64+1)/4

1年前

2

195857508 幼苗

共回答了4个问题 举报

[(5-1)(5+1)(5^2+1)(5^4+1)......(5^32+1)+1]/4
=[(5^2-1)(5^2+1)(5^4+1)...(5^32+1)+1]/4
=(5^64+1)/4

1年前

0
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