分式的加减:1/(x+1)-(x-3)/(x²-1)×(x²-2x+1)/(x-1)(x-3)

伤心自我 1年前 已收到1个回答 举报

大唐李氏 幼苗

共回答了26个问题采纳率:84.6% 举报

1/(x+1)-(x-3)/(x²-1)×(x²-2x+1)/[(x-1)(x-3)]
=1/(x+1)-(x-3)/[(x+1)(x-1)]×(x-1)²/[(x-1)(x-3)]
=1/(x+1)-(x-3)/(x+1)×1/(x-3)
=1/(x+1)-1/[(x+1)
=0

1年前

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