先化简a+1分之1-a²-2a+1分之a+1除以a-1分之a+1,然后从-1.1.根2中选一个作为a的值带入求

[ 1/(a+1) - (a+1)/(a²-2a+1) ] ÷ (a+1)/(a-1)
= [ 1/(a+1) - (a+1)/(a-1)² ] × (a-1)/(a+1)
= [ (a-1)² - (a+1)² ] / [ (a+1)(a-1)² ] × (a-1)/(a+1)
= - 4a / [ (a+1)² (a-1) ]
a只能取根号2
原式 = - 4√2 / [ (√2+1)² (√2 - 1 ) ]
= - 4√2 / (√2 +1)
= - 4√2 (√2 - 1)
= 4√2 - 8

1分之1不就是1吗？应该有括号吧？