pascal编程题目描述　　给定一个整数，请将该数各个位上数字反转得到一个新数。新数也应满足整数的常见形式，即除非给定的

var
st:string;
t:char;
flag:boolean;
len,i:longint;
begin
readln(st);
if st[1] = '-' then
begin
flag:=true;
delete(st,1,1);
end
else flag := false;
len := length(st);
for i := 1 to len div 2 do
begin
t := st[i];
st[i] := st[len - i + 1];
st[len - i + 1] := t;
end;
while (st[1] = '0') and (length(st) > 1) do delete(st,1,1);
if flag then st := '-' + st;
writeln(st);
end.